4^x+1+8=33(2^x)

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Solution for 4^x+1+8=33(2^x) equation:



4^x+1+8=33(2^x)
We move all terms to the left:
4^x+1+8-(33(2^x))=0
determiningTheFunctionDomain 4^x-332^x+1+8=0
We add all the numbers together, and all the variables
4^x-332^x+9=0
We move all terms containing x to the left, all other terms to the right
4^x-332^x=-9

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